Add maths project

Hi, class. I checked up that after applying air resistance, gravity should be lower than the given value.

To prove that, using the formula given, sorry I can t type it ...
But you will derive that T= k(L), where k is the constant 4 PI square over gravity.

Taking an example, T square = 0.201 and L= 5, you will resolve that k =0.0402 and Gravity, G=982.05

If the above example is treated to be the norm, means no air resistance, after adding air resistance, time taken to swing will increase, and therefore a larger value of T.
Taking the above example T square= 0.201 and adding 0.005 as a result of air resistance, the new T becomes 0.206

Now, when T square= 0.206, L=5, you will resolve that k = 0.0412 and Gravity, G= 958.21

That proves that with air resistance, gravity is lower. So the value read should be lower than the actual not higher.


Hope somebody can check this out with our physics teacher. If this is true than we probably cant copy the project given to us.